#include <stdio.h>
int main(){
	int i,branch;
	double a,bon1,bon2,bon4,bon6,bon10;
	bon1=100000*0.1;
	bon2=bon1+100000*0.075;
	bon4=bon2+100000*0.05;
	bon6=bon4+100000*0.03;
	bon10=bon6+400000*0.015;
	printf("请输入利润i:");
	scanf("%d",&i);
	branch=i/100000;
	if(branch>10){
		branch=10;
	}
	switch(branch){
	case 0:a=i*0.1;
	break;
	case 1:a=bon1+(i-100000)*0.075;
	break;
	case 2:
	case 3:a=bon2+(i-200000)*0.05;
	break;
	case 4:
	case 5:a=bon4+(i-400000)*0.03;
	break;
	case 6:
	case 7:
	case 8:
	case 9:a=bon6+(i-600000)*0.015;
	break;
	case 10:a=bon10+(i-1000000)*0.01;
}
	printf("奖金是:%10.2f\n",a);
	return 0;
	}